(16x^4-64x^2)^1/2

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Solution for (16x^4-64x^2)^1/2 equation:


x in (-oo:+oo)

((16*x^4-(64*x^2))^1)/2 = 0

(16*x^4-64*x^2)/2 = 0

16*x^4-64*x^2 = 0

16*x^2*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

16*x^2*(x-2)*(x+2) = 0

(16*x^2*(x-2)*(x+2))/2 = 0

( 16*x^2 )

16*x^2 = 0 // : 16

x^2 = 0

x = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 0, -2, 2 }

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